kkent61 kkent61
  • 04-04-2018
  • Mathematics
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how many real number Solutions does the equation have in 0 equals -7x ^ 2 + 6x + 3

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kiaratatiana7p6mdlk
kiaratatiana7p6mdlk kiaratatiana7p6mdlk
  • 04-04-2018
- 7[tex]7 x^{2} + 6x + 3 = 0 
First step use cuadratic fomula
x = [-b +- \sqrt{ b^{2} -4ac } ]/ 2a[/tex]

a= -7
b=6
c=3
x = [-6 +- \sqrt{ 6^{2} -4(-7)(3) } ]/ 2(-7)
x = [-6 +- \sqrt{ 36 +84 } ]/ -14
x = (3/7 ) +( sqrt(30)/7)
x = (3/7 ) -( sqrt(30)/7)
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