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05-01-2019
Mathematics

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Solve the equation 16y(2–y)+(4y–5)2=0

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dthomasspates dthomasspates

05-01-2019

16y(2−y)+(4y−5)(2)=0

Step 1: Simplify both sides of the equation.

−16y2+40y−10=0

Step 2: Use quadratic formula with a=-16, b=40, c=-10.

y=−b±√b2−4ac2a

y=−(40)±√(40)2−4(−16)(−10)2(−16)

y=−40±√960−32

y=54+−14√15 or y=54+14√15

Answer:

y=54+−14√15 or y=54+14√15

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